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衛(wèi)星物聯(lián)網(wǎng)場景下基于節(jié)點選擇的協(xié)作波束成形技術(shù)研究

席博 洪濤 張更新

席博, 洪濤, 張更新. 衛(wèi)星物聯(lián)網(wǎng)場景下基于節(jié)點選擇的協(xié)作波束成形技術(shù)研究[J]. 電子與信息學(xué)報, 2020, 42(12): 2882-2890. doi: 10.11999/JEIT190707
引用本文: 席博, 洪濤, 張更新. 衛(wèi)星物聯(lián)網(wǎng)場景下基于節(jié)點選擇的協(xié)作波束成形技術(shù)研究[J]. 電子與信息學(xué)報, 2020, 42(12): 2882-2890. doi: 10.11999/JEIT190707
Bo XI, Tao HONG, Gengxin ZHANG. Research on the Collaborative Beamforming Technique Based on the Node Selection for Satellite Internet of Things[J]. Journal of Electronics & Information Technology, 2020, 42(12): 2882-2890. doi: 10.11999/JEIT190707
Citation: Bo XI, Tao HONG, Gengxin ZHANG. Research on the Collaborative Beamforming Technique Based on the Node Selection for Satellite Internet of Things[J]. Journal of Electronics & Information Technology, 2020, 42(12): 2882-2890. doi: 10.11999/JEIT190707

衛(wèi)星物聯(lián)網(wǎng)場景下基于節(jié)點選擇的協(xié)作波束成形技術(shù)研究

doi: 10.11999/JEIT190707
基金項目: 國家自然科學(xué)基金(91738201, 61801445, 61971440)
詳細(xì)信息
    作者簡介:

    席博:男,1996年生,碩博連讀生,研究方向為衛(wèi)星通信

    洪濤:男,1982年生,講師,研究方向為多天線收發(fā)系統(tǒng)、衛(wèi)星通信

    張更新:男,1967年生,教授,博士生導(dǎo)師,研究方向為衛(wèi)星通信、深空通信、空間信息網(wǎng)絡(luò)等

    通訊作者:

    洪濤 hongt@njupt.edu.cn

  • 中圖分類號: TN92

Research on the Collaborative Beamforming Technique Based on the Node Selection for Satellite Internet of Things

Funds: The National Natural Science Foundation of China (91738201, 61801445, 61971440)
  • 摘要:

    針對衛(wèi)星物聯(lián)網(wǎng)(IoT)場景下信號長距離傳輸衰減大以及單個終端節(jié)點傳輸性能受限的問題,該文提出一種基于節(jié)點選擇的協(xié)作波束成形算法,增強終端節(jié)點的傳輸能力。在實際終端位置信息存在誤差的條件下,推導(dǎo)出了協(xié)作波束成形平均方向圖函數(shù),分析了不同系統(tǒng)參數(shù)對于協(xié)作波束成形平均方向圖和瞬時方向圖差異的影響。在此基礎(chǔ)上,根據(jù)衛(wèi)星物聯(lián)網(wǎng)鏈路傳輸性能需求,提出一種區(qū)域分組優(yōu)化的協(xié)作節(jié)點選擇算法。仿真結(jié)果表明,相比于傳統(tǒng)的分布式協(xié)作波束成形節(jié)點選擇算法,該文提出的算法在實際的誤差模型中旁瓣抑制和零陷生成方面具有更好的性能。

  • 圖  1  衛(wèi)星物聯(lián)網(wǎng)場景下協(xié)作波束成形技術(shù)示意圖

    圖  2  節(jié)點選擇模型示意圖

    圖  3  節(jié)點閾值隨誤碼率變化曲線

    圖  4  基于區(qū)域分組策略與基于虛擬陣列優(yōu)化方向圖對比

    圖  5  不同參數(shù)時${C_{m(\phi )}}(z)$隨門限功率z的變化曲線

    圖  6  節(jié)點選擇平均功率方向圖和瞬時功率方向圖對比

    圖  7  區(qū)域分組與虛擬陣選擇節(jié)點的${C_{m(\phi )}}(z)$對比

    圖  8  分組策略算法與基于虛擬陣列算法的收斂性能對比

    圖  9  區(qū)域分組與虛擬陣節(jié)點選擇算法的PSLL性能對比

    表  1  區(qū)域分組節(jié)點選擇算法

     ${\rm{List}}m$=[]:存放$[{A_m}\sim {A_{m + k - 1}}]$中節(jié)點集合;${\rm{List}}m'$=[]:存放$[{A_{M + m}}\sim {A_{M + m + k - 1}}]$中節(jié)點集合;
     ${\rm{List}}C$=[]:存放$[{A_m}\sim {A_{m + k - 1}}]$中用于協(xié)作傳輸節(jié)點集合;${\rm{List}}C'$=[]:存放$[{A_{M + m}}\sim {A_{M + m + k - 1}}]$中用于協(xié)作傳輸節(jié)點集合;
     ${\rm{List}}F$=[]:存放代價函數(shù)值的集合;初始隨機產(chǎn)生$S$個節(jié)點:${P_s}({r_s},{\phi _s}),\;s = 1,2,···,S$;
     $S$:源節(jié)點覆蓋節(jié)點數(shù);$M$:分組對數(shù);$N$:協(xié)作波束成形節(jié)點數(shù);$E$:迭代次數(shù);
      For $s$=1 to $S$ do
       For $m$=1 to $M$ do
        If ${\phi _s} \in [\phi {A_m}\sim \phi {A_{m + k - 1}}]$ then
         ${\rm{List}}m$=${\rm{List}}m$+${P_s}$;
        End
        If ${\phi _s} \in [\phi {A_{M + m}}\sim \phi {A_{M + m + k - 1}}]$ then
         ${\rm{List}}m'$=${\rm{List}}m'$+${P_s}$;
        End
       End
     End
     For $e$=1 to $E$ do
       For $m$=1 to $M$ do
        從${\rm{List}}m$中隨機選擇${{[N} / {\rm{2}}}]$或${{[(N + 1)} / {\rm{2}}}]$個節(jié)點放入${\rm{List}}C$中;
        從${\rm{List}}m'$中隨機選擇${{[N} / {\rm{2}}}]$或${{[(N + 1)} / {\rm{2}}}]$個節(jié)點放入${\rm{List}}C'$中;
        根據(jù)${\rm{List}}C$和${\rm{List}}C'$中的節(jié)點計算代價函數(shù)${f_m}$;
       End
       ${\rm{List}}F$=${\rm{List}}F + {f_m}$;
     End
     Find(min(${\rm{List}}F$(average)))$\xrightarrow{{}}$$\{ {A_{{\rm{best}}}}\sim {A_{{\rm{best}} + k - 1}},{A_{M + {\rm{best}}}}\sim {A_{M + {\rm{best}} + k - 1}}\} $。
    下載: 導(dǎo)出CSV

    表  2  仿真參數(shù)設(shè)計表

    參數(shù)
    衛(wèi)星軌道高度$d$=600 km
    衛(wèi)星天線增益${G_R}$=25 dBi
    衛(wèi)星品質(zhì)因數(shù)${G / T}$=5 ${\rm{dB}}{{\rm{K}}^{ - 1}}$
    空間傳播損耗${L_f}$=168.7 dB
    頻率2.6 GHz
    節(jié)點天線增益(全向天線)${G_s}$=0 dBi
    節(jié)點發(fā)射功率${P_s}$=10 dBm
    調(diào)制方式QPSK
    信息速率${R_b}$=2048 kbps
    無線傳感器網(wǎng)絡(luò)范圍500$ \times $500 m2
    網(wǎng)絡(luò)節(jié)點總數(shù)300
    源節(jié)點覆蓋范圍R=100 m,約60個左右
    定位誤差$B$=1 m,(約10個波長)
    期望/非期望方向(600 km,${30^{ \circ} }$,${0^{ \circ} }$)/(600 km,${30^{ \circ} }$,${1^{ \circ} }$)
    下載: 導(dǎo)出CSV
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  • 收稿日期:  2019-09-16
  • 修回日期:  2020-04-27
  • 網(wǎng)絡(luò)出版日期:  2020-05-28
  • 刊出日期:  2020-12-08

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