基于異構密碼系統(tǒng)的混合群組簽密方案
doi: 10.11999/JEIT180554
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1.
西北師范大學計算機科學與工程學院 ??蘭州 ??730070
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2.
西北師范大學數學與統(tǒng)計學院 ??蘭州 ??730070
Hybrid Group Signcryption Scheme Based on Heterogeneous Cryptosystem
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1.
College of Computer Science and Engineering, Northwest Normal University, Lanzhou 730070, China
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2.
College of Mathematics and Statistics, Northwest Normal University, Lanzhou 730070, China
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摘要:
群組簽密既能實現群組簽名，又能實現群組加密，但是現有的群組簽密方案的發(fā)送者和接收者基本上在同一個密碼系統(tǒng)中，不能滿足現實環(huán)境的需求，而且基本上采用的是公鑰加密技術，公鑰加密技術在加密長消息時效率較低。因此該文提出由基于身份的密碼體制(IBC)到無證書密碼體制(CLC)的異構密碼系統(tǒng)的混合群組簽密方案。在該方案中，私鑰生成器(PKG)和密鑰生成中心(KGC)能夠分別在IBC密碼體制和CLC密碼體制中產生自己的系統(tǒng)主密鑰；而且群組成員只有協作才能解簽密，提高了方案的安全性；同時在無需更換群組公鑰和其他成員私鑰的情況下，用戶可以動態(tài)地加入該群組。所提方案采用了混合簽密，具有可加密任意長消息的能力。在隨機預言模型下，證明了該文方案在計算Diffie-hellman困難問題下具有保密性和不可偽造性。通過理論和數值實驗分析表明該方案具有更高的效率和可行性。
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關鍵詞:
- 無證書密碼學 /
- 異構密碼系統(tǒng) /
- 混合簽密 /
- 基于身份的密碼學 /
- 群組簽密
Abstract:Group signcryption is a cryptosystem which can realize group signature and group encryption. However, the message sender and receiver of existing group signcryption schemes are basically in the same cryptosystem, which does not meet the needs of the real environment and the public key encryption technology is basically used, public key encryption technology in encrypted long message efficiency is too low. Therefore, this paper proposes a hybrid group signcryption scheme based on heterogeneous cryptosystem from Identity-Based Cryptosystem (IBC) to CertificateLess Cryptosystem (CLC). In the scheme, The Private Key Generator (PKG) in the IBC cryptosystem and Key Generation Center (KGC) in the CLC cryptosystem generate their own system master keys, and group members can only solve signcryption through collaboration, which improves the security of the scheme. Meanwhile, the user can dynamically join the group without changing the group public key and other members’ private key. The scheme uses hybrid signcryption and has the ability to encrypt any long message. It is proved that the scheme satisfies confidentiality and unforgeability in computing the Diffie-hellman hard problem in the random oracle model. Theoretical and numerical analysis shows that the scheme is more efficient and feasible.
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表 1 效率分析
方案 簽密階段運算量 解簽密階段運算量 簽密密文長度 文獻[13] $(2{n^2} + 7n + 3){P_M} + 3{P_H}$ $({n^2} + n + 3){P_M} + 3{P_H}$ $2|{G_1}| + 3|{{Z}}_q^*|$ 文獻[15] $(2{n^2} + 3n + 2){P_M} + 3{P_H}$ $({n^2} + n + 2){P_M} + 3{P_H}$ $|{G_1}| + 3|{{Z}}_q^*|$ 本文 $(2n + 7){P_M} + 4{P_H}$ $(2n + 5){P_M} + 3{P_H}$ $|{G_1}| + 4|{{Z}}_q^*|$ 
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表 2 本文方案計算時間(s)
n 100 200 300 400 500 600 700 800 900 1000 簽密時間 1.1861 2.3375 3.6016 4.7899 5.9708 7.1283 8.1671 9.5163 10.7285 11.8963 解簽密時間 1.4792 1.5774 1.7442 1.8645 1.8991 1.9001 2.1469 2.3773 2.4658 2.5549
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