新的具有隱私保護功能的異構聚合簽密方案
doi: 10.11999/JEIT180249
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西北師范大學計算機科學與工程學院 ??蘭州 ??730070
基金項目: 國家自然科學基金(61163038, 61262056, 61262057)，甘肅省高等學?？蒲许椖?2017A-003, 2018A-207)
New Privacy Preserving Aggregate Signcryption for Heterogeneous Systems
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College of Computer Science and Engineering, Northwest Normal University, Lanzhou 730070, China
Funds: The National Natural Science Foundation of China (61163038, 61262056, 61262057), The Higher Educational Scientific Research Foundation of Gansu Province (2017A-003, 2018A-207)
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摘要: 異構聚合簽密方案不僅可以保證異構密碼系統(tǒng)之間數據的機密性和不可偽造性，而且可以提供多個密文批量驗證。該文分析了一個具有隱私保護功能的異構聚合簽密方案的安全性，指出該方案不能抵擋惡意密鑰生成中心(KGC)攻擊，惡意KGC可以偽造有效的單密文和聚合密文。為了提高原方案的安全性，該文提出一種新的具有隱私保護功能的異構聚合簽密方案。該方案克服了原方案存在的安全性問題，實現了無證書密碼環(huán)境到身份密碼環(huán)境之間的數據安全傳輸，在隨機預言機模型下證明新方案的安全性。效率分析表明新方案與原方案效率相當。Abstract: The privacy preserving aggregate signcryption for heterogeneous systems can ensure the confidentiality and unforgeability of the data between heterogeneous cryptosystems, it also can provide multi-ciphertext batch verification. This paper analyzes the security of a scheme with privacy-preserving aggregate signcryption heterogeneous, and points out that the scheme can not resist the attack of malicious Key Generating Center (KGC), it can forge a valid ciphertext. In order to improve the security of the original scheme, a new heterogeneous aggregation signature scheme with privacy protection function is proposed.The new scheme overcomes the security problems existing in the original scheme and ensures the data transmission between the certificateless public key cryptography and the identity-based public key cryptographic, and the security of the new scheme is proved under the random oracle model. Efficiency analysis shows that the new program is equivalent to the original one.
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表 1 基本運算耗費的時間(ms)
${T_{{\rm{add}}}}$ ${T_{{\rm{pm}}}}$ ${T_p}$ ${T_H}$ ${T_h}$ 0.023 3.382 3.711 6.720 1.024 
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表 2 簽密方案效率比較
方案 簽密 解簽密 安全性 Niu方案 $(2n + 5){T_{{\rm{pm}}}} + {T_p} + 2{T_H}+ {T_h}$ $ + (n + 3){T_{{\rm{add}}}} \ge 41.849$ $n{T_{{\rm{pm}}}} + 5{T_p} + 3{T_H} + {T_h}$ $ + (n + 1){T_{{\rm{add}}}} \ge 42.143$ 低 本文方案 $(2n + 5){T_{{\rm{pm}}}} + {T_p} + {\rm{3}}{T_H} + {T_h}$ $ + (n + 3){T_{{\rm{add}}}} \ge 48.569$ $n{T_{{\rm{pm}}}} + 5{T_p} + 3{T_H} + {T_h}$ $ + (n + 1){T_{{\rm{add}}}} \ge 42.143$ 高
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