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一種自動匹配的分布式非圓信號二維DOA快速估計方法

崔維嘉 代正亮 王大鳴 李祥志

崔維嘉, 代正亮, 王大鳴, 李祥志. 一種自動匹配的分布式非圓信號二維DOA快速估計方法[J]. 電子與信息學報, 2018, 40(12): 2881-2888. doi: 10.11999/JEIT171058
引用本文: 崔維嘉, 代正亮, 王大鳴, 李祥志. 一種自動匹配的分布式非圓信號二維DOA快速估計方法[J]. 電子與信息學報, 2018, 40(12): 2881-2888. doi: 10.11999/JEIT171058
Weijia CUI, Zhengliang DAI, Daming WANG, Xiangzhi LI. Fast Two-dimensional DOA Estimation for Coherently Distributed Noncircular Signals with Automatic Pairing[J]. Journal of Electronics & Information Technology, 2018, 40(12): 2881-2888. doi: 10.11999/JEIT171058
Citation: Weijia CUI, Zhengliang DAI, Daming WANG, Xiangzhi LI. Fast Two-dimensional DOA Estimation for Coherently Distributed Noncircular Signals with Automatic Pairing[J]. Journal of Electronics & Information Technology, 2018, 40(12): 2881-2888. doi: 10.11999/JEIT171058

一種自動匹配的分布式非圓信號二維DOA快速估計方法

doi: 10.11999/JEIT171058
基金項目: 國家自然科學基金(61401513)
詳細信息
    作者簡介:

    崔維嘉:男,1976年生,博士,副教授,研究方向為移動通信、信號處理等

    代正亮:男,1993年生,碩士生,研究方向為陣列信號處理、分布式信號處理等

    王大鳴:男,1971年生,博士,講師,研究方向為無線通信、信號處理等

    李祥志:男,1995年生,碩士生,研究方向為陣列信號處理

    通訊作者:

    代正亮  xinxidailiang@outlook.com

  • 中圖分類號: TN911.7

Fast Two-dimensional DOA Estimation for Coherently Distributed Noncircular Signals with Automatic Pairing

Funds: The National Natural Science Foundation of China (61401513)
  • 摘要: 在相干分布式非圓信號2維波達方向(DOA)估計中,針對利用非圓特性后維數(shù)擴展帶來的較大復雜度問題,且現(xiàn)有的低復雜度算法均需要額外的參數(shù)匹配,該文提出一種基于互相關(guān)傳播算子的自動匹配2維DOA快速估計算法。該算法考慮L型陣列,在建立相干分布式非圓信號擴展陣列模型的基礎(chǔ)上,首先證明了L陣中兩個子陣的廣義方向矢量(GSV)均具有近似旋轉(zhuǎn)不變特性,然后通過陣列輸出信號的互相關(guān)運算消除了額外噪聲,最終利用子陣GSV的近似旋轉(zhuǎn)不變關(guān)系通過傳播算子方法得到中心方位角與俯仰角估計。理論分析和仿真實驗表明,所提算法無須譜峰搜索和協(xié)方差矩陣特征分解運算,具有較低的計算復雜度,并且能夠?qū)崿F(xiàn)2維DOA估計的自動匹配;同時,相比于現(xiàn)有的相干分布式非圓信號傳播算子算法,所提算法以較小的復雜度代價獲得了性能的較大提升。
  • 圖  1  L陣列與分布式信源

    圖  2  2維DOA估計分布圖

    圖  3  不同算法2維DOA估計均方根誤差RMSE隨信噪比SNR變化

    圖  4  不同算法2維DOA估計均方根誤差RMSE隨快拍數(shù)變化

    表  1  計算復雜度對比

    算法 計算量
    SOS $O\left(8{M^3} + 4{M^2}N + L({K^3} + 2{K^2}M)\right)$
    TLS-ESPRIT $O\left({(2M + 1)^3} + {(2M + 1)^2}N + 2M{K^2} + 2{K^3}\right)$
    CDNC $O\left(64{M^3} + 16{M^2}N + \left(\frac{{11}}{9}M - 4\right){K^2} + 2{K^3}\right)$
    NC-PM $O\left(2(4M - 1)KN + 2{K^3} + {K^2}\right)$
    本文算法 $O\left(4{M^2}N + 22{M^2}K + 3{K^3} - 12{K^2}\right)$
    下載: 導出CSV
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出版歷程
  • 收稿日期:  2017-11-14
  • 修回日期:  2018-09-26
  • 網(wǎng)絡(luò)出版日期:  2018-10-16
  • 刊出日期:  2018-12-01

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