全負(fù)載蜂窩網(wǎng)絡(luò)下多復(fù)用D2D通信功率分配算法研究
doi: 10.11999/JEIT190974
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吉林大學(xué)通信工程學(xué)院 長(zhǎng)春 130012
Research on Power Allocation Algorithm of Multi-to-One Multiplexing D2D Communication Underlaying Full Load Cellular Networks
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College of Communication Engineering, Jilin University, Changchun 130012, China
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摘要:
針對(duì)全負(fù)載蜂窩網(wǎng)絡(luò)中D2D通信的功率分配問題,該文提出了一種基于非合作完全信息博弈納什均衡解的多復(fù)用D2D通信功率分配算法。以優(yōu)先保證蜂窩用戶通信質(zhì)量與D2D用戶接入率為前提,設(shè)置D2D通信系統(tǒng)上行鏈路幀結(jié)構(gòu),之后建立非合作完全信息博弈系統(tǒng)模型,引入定價(jià)機(jī)制到功率分配博弈模型中并分析納什均衡解的存在性與唯一性,最后給出該模型的分布式迭代求解算法。仿真結(jié)果表明,隨著D2D用戶復(fù)用數(shù)量的增加,該算法在提升系統(tǒng)吞吐量的同時(shí),能有效地控制系統(tǒng)內(nèi)部干擾,大幅度降低系統(tǒng)總能耗。
Abstract:Considering power allocation of D2D (Device to Device) communication in fully loaded cellular networks, a multi-to-one multiplexing D2D communication power allocation algorithm based on the Nash equilibrium solution of non-cooperative complete information game is proposed. The communication quality of cellular users and the access rate of D2D users are guaranteed first, and the uplink frame structure of D2D communication system is given. Then, the non-cooperative complete information game model is established. After that, the pricing mechanism is introduced into the power distribution game model, and the existence and uniqueness of the Nash equilibrium solution are analyzed. Finally, the paper gives a distributed iterative algorithm for the model. The simulation results show that with the increase of the number of D2D pairs, the algorithm not only improves the system throughput, but also controls the internal interference of the system effectively, reduces the total energy consumption of the system greatly.
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Key words:
- Wireless communications /
- D2D communications /
- Power distribution /
- Game theory
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表 1 多復(fù)用D2D通信功率分配算法
算法1:功率分配算法 輸入:$S_{{\rm{max}}}^{D_q},\;\lambda _j^D,\;\varepsilon ,\;\alpha ,\;\chi ,\;{N_0},\;{{{Z}}_{p,q}},\;{{{Y}}_{p,q}}$ 輸出:$S_1^{D_q},\;S_2^{D_q},\;S_3^{D_q},\; ··· ,\;S_q^{D_q},\;{ {{T} }_{{\rm{sum}}} }$ (1) for $i = 1$ to $p$ do (2) calculate ${{{Y}}_{i,i}} = S_i^{C_p}$ (3) if $S_i^{C_p} \ge S_{\max }^{C_p}$ then $S_i^{C_p} = S_{\max }^{C_p}$ (4) end for (5) $t = 0 , {\xi _{i,j}} = 1 , S_j^{D_q}(0) = S_{\max }^{D_q}$ (6) for $i = 1$ to $p$ do (7) for $j = 1$ to $n$ do (8) $t = t + 1$
(9) $S_j^{D_q}(t) = \frac{B}{ {\lambda _j^D\ln 2} } - \dfrac{ {\mu \left[ {\sigma _N^2 \!+\! \displaystyle\sum\limits_{k = 1,k \ne j}^n { {\xi _{i,j} }S_k^{D_q}(t \!-\! 1){H_{j,k} } } } \right]} }{ { {g_j} } }$(10) if $S_j^{D_q}(t) < S_{\min }^{D_q}$ then $S_j^{D_q}(t) = S_{\min }^{D_q}$ (11) if $S_j^{D_q}(t) > S_{\max }^{D_q}$ then $S_j^{D_q}(t) = S_{{\rm{max}}}^{D_q}$ (12) end for (13) if $\left| {S_j^{D_q}(t) - S_j^{D_q}(t - 1)} \right| < \varepsilon ,j \in \left[ {1,n} \right]$ then (14) calculate ${ {{Z} }_{i,j} } , { {{T} }_{{\rm{sum}}} }$ (15) else go to step (8) (16) end for 下載: 導(dǎo)出CSV
表 2 仿真參數(shù)
參數(shù) 數(shù)值 小區(qū)半徑 1000 m 路徑損耗常數(shù)($\alpha $) 0.01 路徑損耗指數(shù)($\chi $) 4 ${N_0}$ –114 dBm/Hz 蜂窩用戶最大發(fā)射功率 48 dBm D2D用戶的最大發(fā)射功率 24 dBm 系統(tǒng)帶寬 180 kHz 多徑衰落 單位均值的指數(shù)分布 陰影衰落 均值為0,標(biāo)準(zhǔn)差為8的正態(tài)分布 蜂窩用戶數(shù) 20 D2D用戶對(duì)數(shù)量 60~140 D2D用戶之間最大距離 50 m 系統(tǒng)誤碼率BER ${10^{ - 4}}$ 下載: 導(dǎo)出CSV
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