車載自組網(wǎng)中可證明安全的無證書認證方案
doi: 10.11999/JEIT190883
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1.
北京電子科技學院 北京 100070
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2.
西安電子科技大學 西安 710000
Provable Security Certificateless Authentication Scheme for Vehicular Ad hoc Network
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1.
Beijing Electronic Science&Technology Institute, Beijing 100070, China
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2.
Xidian University, Xi’an 710000, China
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摘要:
認證協(xié)議的設計是目前車載自組網(wǎng)(VANET)安全領域的研究熱點?,F(xiàn)有的認證方案中普遍存在密鑰托管帶來的安全問題,以及使用計算量大的雙線性對導致認證效率很低。針對以上問題,該文提出可證明安全的無證書批認證方案,方案中車輛的密鑰由車輛自身和一個密鑰生成中心共同生成,解決密鑰需要托管給第三方維護的問題;方案的簽名構(gòu)造不使用計算量大的對運算,減少了計算開銷;引入批認證來減少路邊設施的認證負擔,提高認證效率?;谇蠼鈾E圓曲線上的離散對數(shù)問題的困難性假設,在隨機預言機模型中證明了該方案可以抵抗自適應選擇消息和身份攻擊,從而抵抗更改攻擊和假冒攻擊,并具有匿名性、可追蹤性等特點。與現(xiàn)有方案相比,該方案實現(xiàn)了更高效的認證。
Abstract:The design of authentication protocol is a hot topic in the field of the security of Vehicular Ad hoc NETwork (VANET). There are security problems caused by key escrow in the existing authentication schemes. In order to solve this problem and achieve secure and efficient verification, an efficient pairing-free certificateless authentication scheme with batch verification is proposed, in which the key of the vehicle is generated by the vehicle itself and a key generation center, which solves the problem that the key needs to be managed to the third party for maintenance. The bilinear pairing operation, one of the most complex operations in modern cryptography, is not used in the generation of vehicle’s signatures to reduce the computation cost of message verification. Unforgebility of the schemes against adaptively chosen-message and identity attack is proved under the difficulty of computing the discrete logarithm problem in the random oracle model to guarantee resistancy against modification and impersonation attacks, and has the characteristics of anonymity and traceability. Compared to the existing schemes, the proposed scheme is more efficient.
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Key words:
- Authentication /
- Certificateless /
- Batch verification /
- Provable security /
- Anonymity
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表 1 批認證過程中無效消息查找算法(二分查找算法)
輸入:List={IDi, Mi, Wi, σi, Ti} 輸出:InvalidList={ID1, ID2, ···, IDm} (1) Function (2) batch And Search(List, InvalidList, Index, low, high) (3) /*Function batchAuth(List, low, high)表示對消息數(shù)組下
標Index屬于[low, high]的消息進行式(2)所述批認證,成功
則返回true,失敗則返回false*/(4) if (batchAuth(List, Index Low, high)) then (5) return true (6) else if (low==high) (7) Invalid List.append(List[low]) (8) return Invalid List (9) else (10) mid=(low+high)/2 (11) batch And Search(List, InvalidList, Index, low, mid) (12) batch And Search(List, InvalidList, Index, mid+1,
high)(13) end if (14) return InvalidList (15) end if (16) end Function (17) for i:=1 to n do (18) batch And Search(List, InvalidList, i, 1, n)19: end for 下載: 導出CSV
表 2 不同方案的計算開銷(ms)
方案 簽名生成 認證1條消息 認證n條消息 文獻[15] 5Tmul-G1+1Tpa-G1+1Tmtp=12.9581 Tmul-G1+3Texp+Tmtp=18.7480 nTmul-G1+3Texp+nTmtp=5.1120n+12.6117 文獻[17] 4Tmul-G1+1Tpa-G1+2Tmtp+1Th=15.6552 2Tpar+2Tmul-G1+1Tpa-G1+1Tmtp
+1Th=8.42732Texp+2nTmul-G1+nTpa-G1+nTmtp+nTh
=7.8312n+8.422文獻[12] 5Texp+3Th= 0.0253 Texp+2Tpar+3Th=8.4273 (n+1)Tpar+nTexp+3nTh=4.2163n+4.2110 本文 4Tmul-G+2Tpa-G+3Th=1.7666 4Tmul-G+3Tpa-G+3Th=1.7737 (2 n+2)Tmul-G+3nTh+(2n+1)Tpa-G=
0.8879n+0.8858下載: 導出CSV
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